This article is the second one in our series of "Maths Tricks and Shortcuts for CAT and GMAT". The first article on Maths Tricks is posted here. This article features 38 of the most important ready made formula or tricks which come in handy while answering objective questions on Quantitative Ability (maths) in management entrance tests such as CAT, GMAT etc. Remembering them would help the aspiring candidates a lot in solving more questions in the QA section accurately in a shorter span of time.
If n is any integer , n^2 + 4 is not divisible by 4
[(a+e)/2,(b+f)/2] =[ (c+g)/2 , (d+h)/2]
1/2*base*altitude = 1/2*a*b*sinC = 1/2*b*c*sinA = 1/2*c*a*sinB = root(s*(s-a)*(s-b)*(s-c)) where s=a+b+c/2
=a*b*c/(4*R) where R is the CIRCUMRADIUS of the triangle = r*s ,where r is the inradius of the triangle .
In any triangle
a=b*CosC + c*CosB
b=c*CosA + a*CosC
c=a*CosB + b*CosA
(k1*a1+ k2*a2+k3*a3+..............) / (k1*b1+ k2*b2+k3*b3+..............) , which is also equal to
(a1+a2+a3+............./b1+b2+b3+..........)
a/SinA = b/SinB =c/SinC=2R , where R is the circumradius
2 < e < 3
(m+n)! is divisible by m! * n! .
The equation whose roots are the reciprocal of the roots of the equation ax^2+bx+c is cx^2+bx+a
is((a+c+e)/3 , (b+d+f)/3) .
In a triangle , if AD be the median to the side BC , then
AB^2 + AC^2 = 2(AD^2 + BD^2) or 2(AD^2 + DC^2) .
The HCF and LCM of two nos. are equal when they are equal.
other two sides.
always a rectangle.
else |a|+|b| >= |a+b|
If Q be the volume of a vessel
q qty of a mixture of water and wine be removed each time from a mixture
n be the number of times this operation be done
and A be the final qty of wine in the mixture
then ,
A/Q = (1-q/Q)^n
3,4,5 (3^2=4+5)
5,12,13 (5^2=12+13)
7,24,25 (7^2=24+25)
8,15,17 (8^2 / 2 = 15+17 )
9,40,41 (9^2=40+41)
11,60,61 (11^2=60+61)
12,35,37 (12^2 / 2 = 35+37)
16,63,65 (16^2 /2 = 63+65)
20,21,29(EXCEPTION)
where median is the line joining the midpoints of the oblique sides.
Then
WD^2 + WB^2 = WC^2 + WA^2
Let a be the side of an equilateral triangle. Then if three circles be drawn inside
this triangle touching each other then each has a radius = a/(2*(root(3)+1))
This is used for successive discounts types of sums.
Like in 1999 population increases by 10% and then in 2000 by 5%
So the population in 2000 now is 10+5+(50/100)=+15.5% more that was in 1999
and if there is a decrease then it will be preceded by a negetive sign and likewise.
38 More Math Formulae, Tricks and Shortcuts in QA for CAT and GMAT
Posted by
Grad Street Journalist
on Jul 5, 2008
at
1:23 AM
Area of a hexagon = root(3) * 3 * (side)^2
(1+x)^n ~ (1+nx) if x<<<1
Area of a trapezium = 1/2 * (sum of parallel sides) * height = median * height
When a three digit number is reversed and the difference of these two numbers is taken , the middle number is always 9 and the sum of the other two numbers is always 9 .
Any function of the type y=f(x)=(ax-b)/(bx-a) is always of the form x=f(y) .
Let 'x' be certain base in which the representation of a number is 'abcd' , then the decimal value of this number is a*x^3 + b*x^2 + c*x + d
When you multiply each side of the inequality by -1, you have to reverse the direction of the inequality.
To find the squares of numbers from 50 to 59
For 5X^2 , use the formulae
(5X)^2 = 5^2 +X / X^2
E.g. (55^2) = 25+5 /25
=3025
(56)^2 = 25+6/36
=3136
(59)^2 = 25+9/81
=3481
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2 feedbacks:
the second trick in the 1st one... i.e. n^2+4 not divisible by 4 doesn't seem to be correct. coz any power of 4 + 4 is goin to be divisible by 4.
Thanks a lot for these formulae. I am sure at least one among these will be useful in the CAT exam.
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